java中的math.log是以什么为底
发布时间:2025-05-21 13:52:18 发布人:远客网络
一、java中的math.log是以什么为底
1、在java中求log2N,首先要弄明白一个初中学到的公式log2N=logeN/loge2,logeN代表以e为底的N的对数紶激官刻擢灸规熏海抹,loge2代表以e为底的2的对数.
2、在java.lang.math类中的log(double a)代表以e为底的a的对数,因此log2N在Java中的表示为:
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二、java 获取int类型数据长度的方法
1、valueOf方法返回的相关Number对象持有传递的参数的值。
2、该参数可以是基本数据类型,字符串(String),等等。这个方法是一个静态方法。该方法可以采取两个参数,其中一个是String,另一个是基数。
3、使用语句:int numberOfDigits= String.valueOf(n).length();。
4、java.lang.StrictMath.log10()方法返回以10为底的对数的double值。
5、它包括了一些情况:如果参数为NaN或小于零,那么结果为NaN。如果参数为正无穷大,那么结果为正无穷大。如果参数为正零或负零,那么结果是负无穷大。如果参数等于10N的整数n,那么结果是n。
6、使用语句:int nDigits= floor(log10(abs(the_integer)))+ 1;需要使用inclue math.h库。
7、整数类型,任意一个数字<10就是一位数,实现代码如下:
8、MDN文档--Date.prototyp.valueOf()
三、谁会用java编写“贪吃蛇”小游戏
连连看的代码(基本算法)加了部分注释
public class lianliankan implements ActionListener
static String s="no";//用来纪录点击按钮的信息
int x0=0,y0=0,x=0,y=0,n1=0,n2=0;//用来纪录按钮的位置信息
Button b1,b2,b3,b4,b5,b6,b7,b8,b9,b10;//用比较笨的方法添加了
Button b11,b12,b13,b14,b15,b16,b17,b18;//30个按钮来实现游戏界面
Button b19,b20,b21,b22,b23,b24,b25;//可以用数组实现,这是本人
Button b26,b27,b28,b29,b30,bc;//学java时,入门的联系,所以
Button b,ba,br,bt1,bt2;//有些东西很业余!!嘻嘻
TextField t;//用来显示一些随机信息,方法是下面的guli().
int d[][]={//用来和界面的按钮建立映射关系
public static void main(String[] args)
lianliankan t=new lianliankan();
public void actionPerformed(ActionEvent e)//再来一次按钮的响应事件。
b1=new Button(String.valueOf(d[1][1]));
b2=new Button(String.valueOf(d[1][2]));
b3=new Button(String.valueOf(d[1][3]));
b4=new Button(String.valueOf(d[1][4]));
b5=new Button(String.valueOf(d[1][5]));
b6=new Button(String.valueOf(d[2][1]));
b7=new Button(String.valueOf(d[2][2]));
b8=new Button(String.valueOf(d[2][3]));
b9=new Button(String.valueOf(d[2][4]));
b10=new Button(String.valueOf(d[2][5]));
b11=new Button(String.valueOf(d[3][1]));
b12=new Button(String.valueOf(d[3][2]));
b13=new Button(String.valueOf(d[3][3]));
b14=new Button(String.valueOf(d[3][4]));
b15=new Button(String.valueOf(d[3][5]));
b16=new Button(String.valueOf(d[4][1]));
b17=new Button(String.valueOf(d[4][2]));
b18=new Button(String.valueOf(d[4][3]));
b19=new Button(String.valueOf(d[4][4]));
b20=new Button(String.valueOf(d[4][5]));
b21=new Button(String.valueOf(d[5][1]));
b22=new Button(String.valueOf(d[5][2]));
b23=new Button(String.valueOf(d[5][3]));
b24=new Button(String.valueOf(d[5][4]));
b25=new Button(String.valueOf(d[5][5]));
b26=new Button(String.valueOf(d[6][1]));
b27=new Button(String.valueOf(d[6][2]));
b28=new Button(String.valueOf(d[6][3]));
b29=new Button(String.valueOf(d[6][4]));
b30=new Button(String.valueOf(d[6][5]));
p1.setLayout(new GridLayout(6,5));
bc.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
br.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b1.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b2.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b3.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b4.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b5.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b6.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b7.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b8.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b9.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b10.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b11.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b12.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b13.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b14.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b15.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b16.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b17.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b18.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b19.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b20.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b21.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b22.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b23.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b24.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b25.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b26.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b27.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b28.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b29.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
b30.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
public void ex()//退出界面,可用diolog来实现有模式的类型,更加符合
f1.setLayout(new GridLayout(1,1));
bt1.addMouseListener(new MouseAdapter(){
public void mouseClicked(MouseEvent e)
public void suiji()//产生随机数,来填充游戏界面对应的数组的各个位置
public void chonglie()//重列方法
save[n]=0;//定义一个数组来保存当前的每个按钮位置上的信息
while(n>=0)//产生随机位置,放置按钮
s="no";//这里一定要将按钮点击信息归为初始
public void ling()//将数组中为零的成员对应的按钮消去
{//用按钮类型的数组实现会简化得多,
public void wei(int w1,int w2,Button bz)//判断并纪录每次点击按钮的信息
public void xiao()//这里是整个游戏最重要的部分,就是判断两个按钮在信息
{//相同的情况下能不能消去。仔细分析,不一条条注释
if((x0==x&&(y0==y+1||y0==y-1))||((x0==x+1||x0==x-1)&&(y0==y)))//相邻的情况
for(j=0;j<7;j++)//两个按钮按行分析,看能否消去
for(i=0;i<8;i++)//按列分析,看能不能消去